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12x^2+1x-15=0
We add all the numbers together, and all the variables
12x^2+x-15=0
a = 12; b = 1; c = -15;
Δ = b2-4ac
Δ = 12-4·12·(-15)
Δ = 721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{721}}{2*12}=\frac{-1-\sqrt{721}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{721}}{2*12}=\frac{-1+\sqrt{721}}{24} $
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